4r^2+48=32r

Solution for 4r^2+48=32r equation:

Simplifying
4r2 + 48 = 32r

Reorder the terms:
48 + 4r2 = 32r

Solving
48 + 4r2 = 32r

Solving for variable 'r'.

Reorder the terms:
48 + -32r + 4r2 = 32r + -32r

Combine like terms: 32r + -32r = 0
48 + -32r + 4r2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(12 + -8r + r2) = 0

Factor a trinomial.
4((2 + -1r)(6 + -1r)) = 0

Ignore the factor 4.
Subproblem 1
Set the factor '(2 + -1r)' equal to zero and attempt to solve:

Simplifying
2 + -1r = 0

Solving
2 + -1r = 0

Move all terms containing r to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1r = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1r = 0 + -2
-1r = 0 + -2

Combine like terms: 0 + -2 = -2
-1r = -2

Divide each side by '-1'.
r = 2

Simplifying
r = 2
Subproblem 2
Set the factor '(6 + -1r)' equal to zero and attempt to solve:

Simplifying
6 + -1r = 0

Solving
6 + -1r = 0

Move all terms containing r to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1r = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1r = 0 + -6
-1r = 0 + -6

Combine like terms: 0 + -6 = -6
-1r = -6

Divide each side by '-1'.
r = 6

Simplifying
r = 6
Solution
r = {2, 6}